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3w^2-7w-180=0
a = 3; b = -7; c = -180;
Δ = b2-4ac
Δ = -72-4·3·(-180)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-47}{2*3}=\frac{-40}{6} =-6+2/3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+47}{2*3}=\frac{54}{6} =9 $
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